In
physics,
mechanical work is the amount of
energy transferred by a
force acting through a distance in the direction of the force. Like energy, it is a
scalar quantity, with
SI units of
joules. The term
work was first coined in 1826 by the French mathematician
Gaspard-Gustave Coriolis.
[1][2]
According to the
work-energy theorem, if one or more external forces act upon a rigid object, causing its
kinetic energy to change from
Ek1 to
Ek2, then the mechanical work (
W) done by the
net force is equal to the change in kinetic energy. For translational motion, the theorem can be specified as:
[3]
![W = \Delta E_k = E_{k_2} - E_{k_1} = \tfrac12 m (v_2^2 - v_1^2) \,\!](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_v0muYCs1wiwsumZrnnIBfVf2VJMlbS0_nH5dnVSKd9XwI1d9pWNR0bC_koVvwTPl6IXAh3HtFka8bf3xdk_kt-9-yDC3Mb4TAoJlnweiBb1-beWrOBtDgXLwOZ8xSzTNnnkIXc61o1Nh7056m8Ig=s0-d)
where
m is the
mass of the object and
v is the object's
velocity.
If a force
F that is constant with respect to time acts on an object while the object is displaced in a straight line along the length and direction of a vector
d, the mechanical work done by the force on the object is the
dot product of the
vectors F and
d:
[4]
![W = \bold{F} \cdot \bold{d} = F d \cos\theta](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_tXh_PdgEPNVEtlJjGwjKDnFrifdnVBkjnLtVRrIxIyZRZWDdCrCSFy4kmLOxq384_CBvXaojfsLDMjarZ5nsg_Tz7KTT9rC9mUXgAipG_UbEa4dBU8yNuVjejydE5dy6jWzs7bPfbgiFaAuDHxng=s0-d)
![](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_ufRxU55HX_zxEtp_4PAk0xqJjzfkpejbyj4H2L-eYbtayUr41Y1418OWYsiTYcf5lSfdttmqzSYNYo_PHemwSFmSvG6RJtOm__FMQq4CJG1ontNvlUn-h1HuoQFBCalalUHuz9fkCCMVtaAjwiG4GnjrVzvNYMuHIHMmcp0pyzr191Acv3FVPMh-BbN8oRZB0ODeg0Ww=s0-d)
If the force and the displacement are parallel and in the same direction (
θ = 0), the mechanical work is positive. If the force and the displacement are parallel but in opposite directions (i.e. antiparallel,
θ = 180⁰), the mechanical work is negative. If a force
F is applied at an angle
θ, only the component of the force in the same direction as the displacement (
Fcosθ) does work. Thus, if the force acts perpendicular to the displacement (
θ = 90⁰ or 270⁰), zero work is done by the force.
[4]
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